When 5 consecutive integers are added together and the sum is then multiplied by 5, the result is 225. Which of the following is the largest of the 5 consecutive integers?
Consecutive integers increase by 1 each time you jump from number to number.
x = 1st consecutive integer x + 1 = 2nd consecutive integer x + 2 = 3rd consecutive integer x + 3 = 4th consecutive integer x + 4 = 5th consecutive integer Add the 5 consecutive integers together, multiply by 5, and set equal to 225. 5(x + x + 1 + x + 2 + x + 3 + x + 4) = 225 5(5x + 10) = 225 {combined like terms} 5x + 10 = 45 {divided each side by 5} 5x = 35 {subtracted 10 from each side} x = 7 {divided each side by 5} x + 4 = 11 {substituted 7, in for x, into x + 4} 11 is the largest of the 5 consecutive integers Ask Algebra House
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