What is the equation of the line that passes through the point (-8,0) and is parallel to the line x + 2y = 14 ?
Parallel lines have the same slope.
- Get the equation of the given line in slope-intercept form, in order to see the slope of the line.
Slope-intercept form is y = mx + b
m is the slope
b is the y-intercept
x + 2y = 14
2y = -x + 14 {subtracted x from each side}
y = -(1/2)x + 7 {divided each side by 2}
slope = -1/2
- Substitute the slope and the (x,y) coordinates of the given point into slope-intercept form, in order to get the y-intercept of the new line.
slope = -1/2 and point is (-8,0)
y = mx + b {slope-intercept form}
0 = (-1/2)(-8) + b {substituted point and slope into slope-intercept form}
0 = 4 + b {multiplied}
b = -4 {subtracted 4 from each side}
On the new line, slope is -1/2 and y-intercept is -4
y = (-1/2)x - 4 is the equation of the line passing through (-8,0) and parallel to x + 2y = 14
Ask the House
- Get the equation of the given line in slope-intercept form, in order to see the slope of the line.
Slope-intercept form is y = mx + b
m is the slope
b is the y-intercept
x + 2y = 14
2y = -x + 14 {subtracted x from each side}
y = -(1/2)x + 7 {divided each side by 2}
slope = -1/2
- Substitute the slope and the (x,y) coordinates of the given point into slope-intercept form, in order to get the y-intercept of the new line.
slope = -1/2 and point is (-8,0)
y = mx + b {slope-intercept form}
0 = (-1/2)(-8) + b {substituted point and slope into slope-intercept form}
0 = 4 + b {multiplied}
b = -4 {subtracted 4 from each side}
On the new line, slope is -1/2 and y-intercept is -4
y = (-1/2)x - 4 is the equation of the line passing through (-8,0) and parallel to x + 2y = 14
Ask the House
