What is the equation of the line that passes through the point (-8,0) and is parallel to the line x + 2y = 14 ?

**Parallel lines have the same slope.**

**- Get the equation of the given line in slope-intercept form, in order to see the slope of the line.**

**Slope-intercept form is y = mx + b**

m is the slope

b is the y-intercept

m is the slope

b is the y-intercept

x + 2y = 14

2y = -x + 14 {subtracted x from each side}

y = -(1/2)x + 7 {divided each side by 2}

slope = -1/2

**- Substitute the slope and the (x,y) coordinates of the given point into slope-intercept form, in order to get the y-intercept of the new line.**

slope = -1/2 and point is (-8,0)

y = mx + b {slope-intercept form}

0 = (-1/2)(-8) + b {substituted point and slope into slope-intercept form}

0 = 4 + b {multiplied}

b = -4 {subtracted 4 from each side}

On the new line, slope is -1/2 and y-intercept is -4

**y = (-1/2)x - 4**is the equation of the line passing through (-8,0) and parallel to x + 2y = 14

*Ask the House*