What is the 30th term of the arithmetic sequence 8,11,14,17,20,......?
Since you are looking for the 30th term and the common difference is 3,
start with the first term, 8 and subtract 3 twentynine times to get to the 30th term. 8  3(29) {start with 8 and subtract 3, 29 times} = 8  87 {multiplied 3 by 29} = 95 {subtracted} 95 is the 30th term Ask Algebra House
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