What is an equation of the line that passes through the point (4,1) and is perpendicular to the line 2x − y = 4?
Find the slope of the given line.
2x - y = 4 -y = -2x + 4 {subtracted 2x from each side} y = 2x - 4 {divided each side by -1} slope of given line is 2 Perpendicular lines have slopes which are negative reciprocals. slope of new line is -1/2 Substitute the point and slope into slope-intercept form. slope is -1/2 and the point is (4,1) y = mx + b {slope-intercept form} 1 = (-1/2)(4) + b {substituted into slope-intercept form} 1 = -2 + b {multiplied -1/2 by 4} b = 3 {added 2 to each side} y-intercept is 3 Substitute slope and y-intercept into slope-intercept form. y = (-1/2) x + 3 is the equation of the line Ask Algebra House
0 Comments
Your comment will be posted after it is approved.
Leave a Reply. |
Latest Videos
Archives
February 2025
|