Gina is 3 years older than Ana. Six years ago she was twice as old. What are their ages now?
x = Ana’s age right now
x + 3 = Gina’s age right now {Gina is 3 years older than Ana (right now)} x  6 = Ana’s age 6 years ago {subtracted 6 from Ana’s current age, above} x  3 = Gina’s age 6 years ago {subtracted 6 from Gina’s current age, above} x  3 = 2(x  6) {six years ago, Gina (x  3) was twice as old as Ana (x  6)} x  3 = 2x  12 {used distributive property} x = 9 {subtracted x from and added 12 to each side} x + 3 = 12 {substituted 9, in for x, into x + 3} Ana is 9 now Gina is 12 now Ana was 3 six years ago Gina was 6 six years ago {twice as old as Ana} Ask Algebra House
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