Two consecutive even integers with a product of 224

Find two consecutive even integers with a product of 224.

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x = first even integer
x + 2 = second consecutive even integer

x(x + 2) = 224 {their product is 224}
x² + 2x = 224 {used distributive property}
x² + 2x - 224 = 0 {subtracted 224 from each side}
​(x + 16)(x - 14) = 0 {factored into two binomials}
x + 16 = 0 or x - 14 = 0 {set each factor equal to zero}
x = -16 or x = 14 {solved each equation for x}
x + 2 = -14 or x = 16 {substituted -16 and 14, in for x, into x + 2}

14 and 16 are the two consecutive even integers
or
-16 and -14 {if accepting negative integers}

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