What is the P(1,3,2,5) on 4 rolls of a die?
If you mean the probability of getting a 1, then a 3, then a 2, and then a 5, it goes like this:
P(1) = 1/6 P(3) = 1/6 P(2) = 1/6 P(5) = 1/6 The probability of getting a 1, then a 3, then a 2, and then a 5 would require multiplying these together. P(1,3,2,5) = 1/6 x 1/6 x 1/6 x 1/6 = 1/1296 Ask Algebra House
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