Find four consecutive even integers with a sum of 60.
x = first even integer
x + 2 = second even integer {even integers increase by 2} x + 4 = third even integer x + 6 = fourth even integer x + x + 2 + x + 4 + x + 6 = 60 {added the four integers and set equal to 60} 4x + 12 = 60 {combined like terms} 4x = 72 {subtracted 12 from each side} x = 18 {divided each side by 4} x + 2 = 16 {substituted 18, in for x, into x + 2} x + 4 = 14 {substituted 18, in for x, into x + 4} x + 6 = 12 {substituted 18, in for x, into x + 6} 18, 16, 14, and 12 are the four consecutive even integers. Ask the House
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