Find four consecutive even integers with a sum of -60.
x = first even integer
x + 2 = second even integer {even integers increase by 2} x + 4 = third even integer x + 6 = fourth even integer x + x + 2 + x + 4 + x + 6 = -60 {added the four integers and set equal to -60} 4x + 12 = -60 {combined like terms} 4x = -72 {subtracted 12 from each side} x = -18 {divided each side by 4} x + 2 = -16 {substituted -18, in for x, into x + 2} x + 4 = -14 {substituted -18, in for x, into x + 4} x + 6 = -12 {substituted -18, in for x, into x + 6} -18, -16, -14, and -12 are the four consecutive even integers. Ask the House
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