One number is 2 more than 3 times another. Their product is 16. Find the numbers.
x = one number
3x + 2 = other number {one number is 2 more than 3 times the other} x(3x + 2) = 16 {their product is 16} 3x² + 2x = 16 {used distributive property} 3x² + 2x  16 = 0 {subtracted 16 from each side} (3x + 8)(x  2) = 0 {factored into two binomials} 3x + 8 = 0 or x  2 = 0 {set each factor equal to zero} x = 8/3 or x = 2 {solved each equation} 3x + 2 = 6 or 3x + 2 = 8 {substituted 8/3 and 2, in for x, into 3x + 2} The two sets of numbers could be 8/3 and 6, or 2 and 8. Ask Algebra House
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