Find two consecutive integers whose sum is 116.
x = first consecutive integer
x + 1 = second consecutive integer x + x + 1 = 116 {added the two integers and set equal to 116} 2x + 1 = 116 {combined like terms} 2x = 117 {subtracted 1 from each side} x = 117/2 {divided each side by 2} Not going to happen. Integers are the positive and negative whole numbers and zero. They do not include fractions. Ask the House
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