The second of three numbers is one less than the first. The third number is 5 less than twice the second. If the third number exceeds the first number by 12, find the three numbers.
x = first number
x  1 = second number {the second is one less than the first} 2(x  1)  5 = third number {the third is 5 less than twice the second} 2(x  1)  5 = x + 12 {the third number exceeds the first by 12} 2x  2  5 = x + 12 {used distributive property} 2x  7 = x + 12 {combined like terms} x = 19 {subtracted x and added 12 to each side} x  1 = 18 {substituted 19, in for x, into x  1} 2(x  1)  5 = 31 {substituted 19, in for x, into 2(x  1)  5} the three numbers are 19, 18, and 31 Ask Algebra House
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