The second of three numbers is one less than the first. The third number is 5 less than twice the second. If the third number exceeds the first number by 12, find the three numbers.
x = first number
x - 1 = second number {the second is one less than the first} 2(x - 1) - 5 = third number {the third is 5 less than twice the second} 2(x - 1) - 5 = x + 12 {the third number exceeds the first by 12} 2x - 2 - 5 = x + 12 {used distributive property} 2x - 7 = x + 12 {combined like terms} x = 19 {subtracted x and added 12 to each side} x - 1 = 18 {substituted 19, in for x, into x - 1} 2(x - 1) - 5 = 31 {substituted 19, in for x, into 2(x - 1) - 5} the three numbers are 19, 18, and 31 Ask Algebra House
0 Comments
Your comment will be posted after it is approved.
Leave a Reply. |
Latest Videos
Archives
September 2024
|