Jonathan is now three times as old as his son is. Twelve years ago, he was six times as old as his son was. Find the present age of each.
x = son's age now
3x = Jonathan's age now {Jonathan is three times as old as his son} x  12 = son's age 12 years ago {subtracted 12 from current age} 3x  12 = Jonathan's age 12 years ago {subtracted 12 from current age} 3x  12 = 6(x  12) {twelve years ago, Jonathan was six times his son's age} 3x  12 = 6x  72 {used distributive property} 3x = 60 {subtracted 6x and added 12 to each side} x = 20 {divided each side by 3} 3x = 60 {substituted 20, in for x, into 3x} Jonathan is 60 his son is 20 Ask Algebra House
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