Jonathan is now three times as old as his son is. Twelve years ago, he was six times as old as his son was. Find the present age of each.
x = son's age now {Jonathan is three times as old as his son}3x = Jonathan's age now x - 12 = son's age 12 years ago {subtracted 12 from current age}3x - 12 = Jonathan's age 12 years ago {subtracted 12 from current age}3x - 12 = 6(x - 12) {twelve years ago, Jonathan was six times his son's age} 3x - 12 = 6x - 72 {used distributive property} -3x = -60 {subtracted 6x and added 12 to each side} x = 20 {divided each side by -3} 3x = 60 {substituted 20, in for x, into 3x} Jonathan is 60 his son is 20 Ask Algebra House
0 Comments
Your comment will be posted after it is approved.
## Leave a Reply. |