Twenty ounces of a 40% gold alloy are mixed with 80 oz of a 10% gold alloy. Find the percent concentration of the resulting gold alloy.
x = concentration of resulting gold alloy
0.4(20) + 0.1(80) = x(20 + 80) {changed percents to decimals and multiplied…20 + 80 is total ounces} 8 + 8 = 100x {multiplied and added in parentheses} 16 = 100x {added 8 and 8} x = 0.16 {divided each side by 100} 16% is the percent concentration of the resulting gold alloy {changed decimal to percent} Ask the House
0 Comments
Your comment will be posted after it is approved.
Leave a Reply. 
Latest Videos
Archives
May 2024
