Find the 60th term of the arithmetic sequence 14, 25, 36.....
The common difference is 11, because it is subtracting 11 each time it jumps from term to term.
Start with the first term, 14, and subtract 11, fiftynine times to arrive at the 60th term. 14  11(59) = 14  649 {multiplied 11 by 59} = 663 {subtracted} 663 is the 60th term Ask Algebra House
0 Comments
Your comment will be posted after it is approved.
Leave a Reply. 
Latest Videos
Archives
September 2023
