How do you factor x² + xy  6y² ?
x² + xy  6y²
= (x + 3y)(x  2y)  The first terms, x and x, multiply to make x².  The last term coefficients of the two binomials multiply to make the last coefficient, 6, and add to make the middle coefficient, 1. Also, the last terms have y attached to them, due to the y in the middle term and the last term. Check with the FOIL method / distributive property: (x + 3y)(x  2y) = x(x) + x(2y) + 3y(x) + 3y(2y) = x²  2xy + 3xy  6y² = x² + xy  6y² Ask Algebra House
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