Evaluate 8a + 3(c  b), when a = 2, b = 1, and c = 3
8a + 3(c  b), when a = 2, b = 1, and c = 3
= 8(2) + 3(3  1) {substituted in for a,b, and c} = 16 + 3(2) {multiplied 8 by 2, and worked inside parentheses} = 16 + 6 {multiplied 3 by 2} = 10 {added} Ask Algebra House
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