The first four terms of a sequence are given.
7, 11, 15, 19, ..... The pattern of the sequence continues in the same manner. Jontae creates a function, f, to calculate the xth term of the sequence where f(1) = 7. Which function did Jontae create? A.) f(x) = 4x B.) f(x) = x + 4 C.) f(x) = 4x + 3 D.) f(x) = 3(x + 1)
You are looking for a function, so that when you substitute 1 in for x, the value of f(x) is equal to 7.
Try f(x) = 4x + 3 f(1) = 4(1) + 3 {substituted 1 in for x} = 4 + 3 {multiplied 4 by 1} = 7 {added} When you substitute 1, in for x, into f(x) = 4x + 3, the value of f(1) is 7. C.) f(x) = 4x + 3 is the correct function. Furthermore, if you substitute 2 in for x, f(2) should be equal to the second term, which is 11. f(x) = 4x + 3 f(2) = 4(2) + 3 {substituted 2 in for x} = 8 + 3 {multiplied 4 by 2} = 11 {added} Also, if you substitute 3 in for x, f(3) should be equal to the third term, which is 15. f(x) = 4x + 3 f(3) = 4(3) + 3 {substituted 3 in for x} = 12 + 3 {multiplied 4 by 3} = 15 {added} As you can probably guess, if you substitute 4 in for x, f(4) will be equal to the fourth term, which is 19. Ask Algebra House
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