The graph of a system of inequalities is shown.

Create the system of inequalities that is represented by the graph.

Determine the boundary line of each of the two inequalities first.

It is necessary to determine the y-intercept, slope, and inequality sign of each boundary line.

A dashed boundary line designates using a < or > sign.

A solid boundary line designates a ≤ or ≥ sign.

An inequality shaded above the line uses a > or ≥ sign.

An inequality shaded below the boundary line uses a < or ≤ sign.

Slope-intercept form is y = mx + b

m is the slope of the line

b is the y-intercept of the line

One line has a y-intercept of -3 and a slope of 0, with a dashed boundary line. Also it is shaded below the line, indicating

the use of a < sign.

y < -3 {slope is zero and the y-intercept is -3}

The other line has a y-intercept of -5 and a slope of 2/3. Also, it is shaded above the line, indicating the use of a ≥ sign

y ≥ (2/3)x - 5 {slope is 2/3 and the y-intercept is -5}

The system of inequalities is:

It is necessary to determine the y-intercept, slope, and inequality sign of each boundary line.

A dashed boundary line designates using a < or > sign.

A solid boundary line designates a ≤ or ≥ sign.

An inequality shaded above the line uses a > or ≥ sign.

An inequality shaded below the boundary line uses a < or ≤ sign.

Slope-intercept form is y = mx + b

m is the slope of the line

b is the y-intercept of the line

One line has a y-intercept of -3 and a slope of 0, with a dashed boundary line. Also it is shaded below the line, indicating

the use of a < sign.

y < -3 {slope is zero and the y-intercept is -3}

The other line has a y-intercept of -5 and a slope of 2/3. Also, it is shaded above the line, indicating the use of a ≥ sign

y ≥ (2/3)x - 5 {slope is 2/3 and the y-intercept is -5}

The system of inequalities is:

**y < -3**

y ≥ (2/3)x - 5y ≥ (2/3)x - 5

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