Which expression is equivalent to (2r² + r  1)  (3r² + 4r  5) ? A.) r²  3r + 4 B.) r² + 5r  6 C.) 5r²  3r + 4 D.) 5r² + 5r  6 (2r² + r  1)  (3r² + 4r  5)
= 2r² + r  1  3r²  4r + 5 {removed parentheses, distributing negative sign} = r²  3r + 4 {combined like terms} A.) r²  3r + 4 Ask Algebra House Comments are closed.

Algebra 1 State Test Practice Archives
January 2020
