A linear function is represented by the table below. Draw a line on the coordinate grid that has a greater
yintercept than the function represented by the table and is perpendicular to the function y + (1/4)x = 2. x y 1 6 1 2 3 2
Find the slope of the line represented by the given table.
y2  y1  = slope of a line x2  x1 (1,6) and (1,2) are two given points. 2  (6)  = slope of the line given by the table {substituted coordinates into slope formula} 1  (1) 4  = slope of the line {simplified in numerator and denominator} 2 slope = 2 Find the yintercept of the line represented by the given table. Slopeintercept form is y = mx + b m is the slope b is the yintercept (1,6) and m = 2 are a point and slope of the line represented by the given table. 6 = 2(1) + b {substituted point and slope into slopeintercept form} 6 = 2 + b {multiplied 2 by 1} b = 4 {added 2 to each side} Find the slope that is perpendicular to the line represented by the given equation. Perpendicular lines have slopes which are negative reciprocals. The given equation is y + (1/4)x = 2. y = (1/4)x + 2 {subtracted (1/4)x from each side} slope = 1/4 {slopeintercept form is y = mx + b, where m is the slope} perpendicular slope is 4 {perpendicular lines have slopes which are negative reciprocals} A line that has a greater yintercept than the line represented by the given table and perpendicular to the line y + (1/4)x = 2 could be: y = 4x + 1 To graph:  put a point on 1 on the yaxis {1 is the yintercept of this line}  from there, move up 4 and to the right 1 and put another point {slope is 4, thus rise is 4 and run is 1} Comments are closed.

Algebra 1 State Test Practice Archives
January 2020
