If a number is chosen at random from the set {-10, -5, 0, 5, 10}, what is the probability that it is a member of the solution set of both 3x - 2 < 10 and x + 2 > -8? A.) 0 B.) 1/5 C.) 2/5 D.) 3/5 E.) 4/5 Find the solution set of each given inequality: 3x - 2 < 10 3x < 12 {added 2 to both sides} x < 4 {divided both sides by 3} x + 2 > - 8 x > -10 {subtracted 2 from both sides} the solution set of both would be -10 < x < 4 in other words, any number between -10 and 4number of successes ----------------------------- = Probability number of possibilities A success chosen from that given set at random would be - 5 or 0, because those numbers are between -10 and 4......and there are 5 possibilities from that set2 --- = Probability 5 C.) 2/5
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