If a number is chosen at random from the set {-10, -5, 0, 5, 10}, what is the probability that it is a member of the solution set of both 3x - 2 < 10 and x + 2 > -8?

A.) 0

B.) 1/5

C.) 2/5

D.) 3/5

E.) 4/5

A.) 0

B.) 1/5

C.) 2/5

D.) 3/5

E.) 4/5

Find the solution set of each given inequality:

3x - 2 < 10

3x < 12 {added 2 to both sides}

x < 4 {divided both sides by 3}

x + 2 > - 8

x > -10 {subtracted 2 from both sides}

the solution set of both would be -10 < x < 4

in other words, any number

**between -10 and 4**

number of successes

----------------------------- = Probability

number of possibilities

A success chosen from that given set at random would be

**- 5 or 0**,

because those numbers are

**between -10 and 4**......and there are

**5 possibilities**from that set

2

--- = Probability

5

**C.) 2/5**