Probability {ACT}

If a number is chosen at random from the set {-10, -5, 0, 5, 10}, what is the probability that it is a member of the solution set of both 3x - 2 < 10 and x + 2 > -8?
A.)  0
B.)  1/5
C.)  2/5
D.)  3/5
E.)  4/5

Find the solution set of each given inequality:
3x - 2 < 10
3x < 12 {added 2 to both sides}
x < 4 {divided both sides by 3}

x + 2 > - 8
x > -10 {subtracted 2 from both sides}

the solution set of both would be -10 < x < 4
in other words, any number between -10 and 4

number of successes 
----------------------------- = Probability
number of possibilities

A success chosen from that given set at random would be - 5 or 0,
because those numbers are between -10 and 4......and there are 5 possibilities from that set

2 
--- = Probability
5

C.)  2/5