In the xy-plane, line l is perpendicular to the graph of the function f(x) = 5x - 2.

Line l could be the graph of which of the following functions?

A.) g(x) = -5x

B.) g(x) = (-1/5)x

C.) g(x) = x - 2

D.) g(x) = (1/5)x

E.) g(x) = 5x

Line l could be the graph of which of the following functions?

A.) g(x) = -5x

B.) g(x) = (-1/5)x

C.) g(x) = x - 2

D.) g(x) = (1/5)x

E.) g(x) = 5x

Slope-intercept form is y = mx + b {in function notation it is f(x) = mx + b}

m is the slope

b is the y-intercept

Perpendicular lines have slopes which are negative reciprocals of each other.

In f(x) = 5x - 2

the slope is 5

To find the line perpendicular to that,

you need a line with a slope of (-1/5) {the negative reciprocal of 5}

**B.) g(x) = (-1/5)x**is perpendicular to the given line

**- Algebra House**