2x + 5

x - 2 = --------

3

A.) -6 < x < 11

B.) 11 ≤ x < 15

C.) 6 < x ≤ 10

D.) -5 < x ≤ -3

E.) -11 < x ≤ -2

x - 2 = --------

3

3(x - 2) = 2x + 5 {multiplied each side by 3, clearing out fraction}

3x - 6 = 2x + 5 {used distributive property}

x = 11 {added 6 and subtracted 2x from each side}

**B.) 11 ≤ x < 15**contains the solution x = 11

**Ask Algebra House**