When the smaller of two consecutive integers is added to four times the larger, the result is 49.

Find the two integers

Find the two integers

x = first consecutive integer

x + 1 = second consecutive integer

x + 4(x + 1) = 49 {the smaller is added to 4 times the larger to equal 49}

x + 4x + 4 = 49 {used distributive property}

5x + 4 = 49 {combined like terms}

5x = 45 {subtracted 4 form each side}

x = 9 {divided each side by 5}

x + 1 = 10 {substituted 9, in for x, into x + 1}

x + 1 = second consecutive integer

**{consecutive integers increase by 1}**x + 4(x + 1) = 49 {the smaller is added to 4 times the larger to equal 49}

x + 4x + 4 = 49 {used distributive property}

5x + 4 = 49 {combined like terms}

5x = 45 {subtracted 4 form each side}

x = 9 {divided each side by 5}

x + 1 = 10 {substituted 9, in for x, into x + 1}

**9 and 10**are the two consecutive integers*- Algebra House*