Bruce has $5.50 in dimes and quarters. He has 8 more quarters then dimes.

How many coins does he have?

How many coins does he have?

x = number of dimes

x + 8 = number of quarters {he has 8 more quarters than dimes}

10x + 25(x + 8) = 550 {value of coin times number of coins equals total value}

10x + 25x + 200 = 550 {used distributive property}

35x + 200 = 550 {combined like terms}

35x = 350 {subtracted 200 from each side}

x = 10 {divided each side by 35}

x + 8 = 18 {substituted 8, in for x, into x + 8}

x + 8 = number of quarters {he has 8 more quarters than dimes}

10x + 25(x + 8) = 550 {value of coin times number of coins equals total value}

10x + 25x + 200 = 550 {used distributive property}

35x + 200 = 550 {combined like terms}

35x = 350 {subtracted 200 from each side}

x = 10 {divided each side by 35}

x + 8 = 18 {substituted 8, in for x, into x + 8}

**10 dimes and 18 quarters***- Algebra House*