Find the length of LO if 6x - 2 = LM, MO = 10, and LO = 11X - 7

LO is a straight line:

6x - 2 + 10 = 11x - 7 {LM + MO = LO}

6x + 8 = 11x - 7 {combined like terms}

8 = 5x - 7 {subtracted 6x from both sides}

15 = 5x {added 7 to both sides}

x = 3 {divided both sides by 5}

LO = 6x - 2

= 6(3) - 2 {substituted 3, in for x, into 6x - 2}

= 18 - 2 {multiplied 6 by 3}

6x - 2 + 10 = 11x - 7 {LM + MO = LO}

6x + 8 = 11x - 7 {combined like terms}

8 = 5x - 7 {subtracted 6x from both sides}

15 = 5x {added 7 to both sides}

x = 3 {divided both sides by 5}

LO = 6x - 2

= 6(3) - 2 {substituted 3, in for x, into 6x - 2}

= 18 - 2 {multiplied 6 by 3}

**LO = 16**{subtracted}*© Algebra House*