The distance, s (in feet), that an object on the moon will fall in the seconds is given by s(t) = 2.735t².

How far will an object fall on the moon in 3 seconds?

How far will an object fall on the moon in 3 seconds?

**If t = 3 seconds**

s(t) = 2.735t²

s(3) = 2.735(3)² {substituted 3 for t}

= 2.735(9) {evaluated exponent}

=

**24.615 ft**{multiplied}

**- Algebra House**