__2y__=

__y - 1__, then y =

9 3

A.) 1/3

B.) 3/5

C.) 4/9

D.) 9/4

E.) 3

**To solve a proportion, cross-multiply.**

__=__

2y

2y

__y - 1__

9 3

2y(3) = 9(y - 1) {cross-multiplied}

6y = 9y - 9 {multiplied and used the distributive property}

-3y = -9 {subtracted 9y from each side}

y = 3 {divided each side by -3}

**E.) 3**

*- Algebra House*